1.

What will be the product of reaction, ""_(101)^(255)Md (alpha, 2n)?

Answer»

`""_(103)^(256)Lr`
`""_(102)^(257)No`
`""_(103)^(257)Lr`
`""_(82)^(205)Pb`

Solution :`""_(101)^(255)Md + ""_(2)^(4)ALPHA to ""_(103)^(257)Lr + 2 ""_(0)^(1)n`


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