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What will be the resistance of a semi circle shown in fig., between its two end faces. Given that radial thickness is 3cm, axial thickness is 4 cm, inner radius is 6 cm and specific resistance is 4xx10^(-6)" ohm "-cm |
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Answer» Solution :`R=(rhol)/(A)=(rho pi((r_(1)+r_(2)))/(2))/(A)` `R=(4xx10^(-6)(pi((6+9)/(2))))/(12)` `R=(4xx10^(-6)(pi(7.5)))/(12)=7.85xx10^(-6)OMEGA` 
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