What will be the shape of Rankine oval when U*y+ ((-u/2*pi*r) = 0?(a) open curve(b) closed body profile(c) straight line(d) pointThe question was posed to me by my school teacher while I was bunking the class.My question comes from Nonlifting Flow over Cylinder in division Inviscid & Incompressible Flow of Aerodynamics

What will be the shape of Rankine oval when U*y+ ((-u/2*pi*r) = 0?(a)

1.	What will be the shape of Rankine oval when Uy+ ((-u/2pi*r) = 0?(a) open curve(b) closed body profile(c) straight line(d) pointThe question was posed to me by my school teacher while I was bunking the class.My question comes from Nonlifting Flow over Cylinder in division Inviscid & Incompressible Flow of Aerodynamics
Answer» Right answer is (b) closed body profile The best I can explain: The shape of the Rankine oval of EQUAL AXES can be given by substituting the STREAM function as zero in the equation Ψ = Uy + ((-u/2pir)sin θ. When Uy+ ((-u/2pi*r) =0, a closed profile body is a circular cylinder of radius R with the CENTRE on the doublet.

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