1.

What will be the temperature at which a solution containing 6 g of glucose per 1000 g water with boil, if molal elevation constant for water is 0.52/1000 g.

Answer»

`1000.173^(@)`C
`100.0173^(@)`C
`100.173^(@)`C
None

Solution :w=6g, W=1000g, Mol. WT. of GLUCOSE= 180
`DeltaT_(b)=(1000xxK_(b)xxw)/(180xx1000)=0.0173^(@)C`
HENCE boiling point of solution =b.p of WATER +
`DeltaT_(b)=100+0.0173^(@)C`


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