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What will be the value of \(\lim\limits_{x \rightarrow 1} x^{\frac{1}{1-x}}\)?(a) 1/e(b) e(c) 0(d) 1I have been asked this question by my college professor while I was bunking the class.The doubt is from First Order Derivative in section Limits and Derivatives of Mathematics – Class 11

Answer»

The CORRECT choice is (a) 1/e

Explanation: We have, y = x^(1/(1 – x))

So, log y = (log x)/(1 – x)

So, \(\lim\limits_{x \rightarrow 1}\)log y = \(\lim\limits_{x \rightarrow 1}\)(log x)/(1 – x)

Now, using L’HOSPITAL’s rule,

\(\lim\limits_{x \rightarrow 1}\)log y = \(\lim\limits_{x \rightarrow 1}\)((\(\FRAC{1}{x})\) / – 1)

=>, \(\lim\limits_{x \rightarrow 1}\)log y = -1

So, \(\lim\limits_{x \rightarrow 1} x^{\frac{1}{1-x}}\) = 1/e.



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