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What would be the accelearation due to gravity at a depth of 200 km from ythe earth surface assuming that earth has uniform denisty [Take ,R =6400 km]A. 4.37 `ms^(-2)`B. 6.737 `ms^(-2)`C. 5.709 `ms^(-2)`D. 4.751 `ms^(-2)` |
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Answer» Given depth d= 2000km =`=2x10^(6)m` Radius of earth R=6400 km `=6.4xx10^(6)`m The acceleration due to gravity at a point at a depth d from the earth surface is given by `g_(d)=g[1-(d)/(R )]` `therefore g_(d)=9.8[(1-(2xx10^(6))/(6.4xx10^(6)))]` `=(9.8xx4.4)/(6.4)=6.737 ms^(-2)` |
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