1.

What would be the radius of second orbit of He^(+) ions?

Answer»

`1.058 Å`
`3.023 Å`
`2.068 Å`
`4.458 Å`

SOLUTION :`r_(n) = (n^(2))/(Z) r_(1)`
For `He^(+) ion, n = 2, Z = 2`
`THEREFORE r_(2) = (4)/(2)xx0.529 Å = 1.058 Å`


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