When 0.1 mol CoCl_(3)(NH_(3))_(5) is treated with excess of AgNO_(3), – InterviewSolution

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1.	When 0.1 mol CoCl_(3)(NH_(3))_(5) is treated with excess of AgNO_(3), 0.2 mole of AgCl are obtained. The conductivity of solution will correspond to
Answer» 1:3 electrolyte 1:2 electrolyte 1:1 electrolyte 3:1 electrolyte Answer :B

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