When `0.1 ` mole of a gas absorbs 41.75 J of heat, the rise in temperature occurs equal to `20^(@)C`. The gas must beA. triatomicB. diatomicC. polyatomicD. monoatomic

When `0.1 ` mole of a gas absorbs 41.75 J of heat, the rise in tempera

1.	When `0.1 ` mole of a gas absorbs 41.75 J of heat, the rise in temperature occurs equal to `20^(@)C`. The gas must beA. triatomicB. diatomicC. polyatomicD. monoatomic
Answer» Correct Answer - B `C_(v) ` ( heat absorbedper degree rise per mole) `=( 41.75J)/( 0.1 mol xx 20^(@)) = 20.875 JK^(-1) mol^(-1)` `C_(p) = C_(v) + R = 20.875 + 8.314 JK^(-1) mol^(-1)` `= 29.189 JK^(-1) mol^(-1)` `(C_(p))/( C_(v)) = ( 29.189)/( 20.875) = 1.40`. Hence, the gas is diatomic.

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When `0.1 ` mole of a gas absorbs 41.75 J of heat, the rise in temperature occurs equal to `20^(@)C`. The gas must beA. triatomicB. diatomicC. polyatomicD. monoatomic

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