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when 1.8 g of steam at the normal boiling point of water is converted inot water ,at the same temperature , enthalpy and entropy changes respectively will be ` [given , DeltaH_("vap")for water =40.8 KJ mol^(-1) ]`A. `-8.12kJ,11 .89Jk^(-1)`B. `10.25 kJ,12 .95 Jk ^(-1)`C. `- 4.08 kJ,-10.93 JK^(-1)`D. `10.93 KJ, -4.08 JK^(-1)` |
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Answer» Correct Answer - c ` DeltaH("condensation") for 1.8 g of steam ` ` = (-40.8)kJ xx (1.8/18) mol =- 4.08 KJ` ` DeltaS= (DeltaH)/(T_(b))= (-4.08xx10^(3)J)/(373.15 K ) =- 10.93 JK^(-1)` |
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