When `1 kg` of ice at `0^(@)C` melts to water at `0^(@)C`, the resulting change in its entropy, taking latent heat of ice to be `80 cal//g` isA. `8xx10^(4)cal//K`B. `80cal//K`C. `293 cal//K`D. `273 cal//K`

When `1 kg` of ice at `0^(@)C` melts to water at `0^(@)C`, the resulti

1.	When `1 kg` of ice at `0^(@)C` melts to water at `0^(@)C`, the resulting change in its entropy, taking latent heat of ice to be `80 cal//g` isA. `8xx10^(4)cal//K`B. `80cal//K`C. `293 cal//K`D. `273 cal//K`
Answer» Correct Answer - C change in entropy `DeltaS = (ml)/(T) = (1000xx80)/(273)=293 cal K^(-1)`.

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When `1 kg` of ice at `0^(@)C` melts to water at `0^(@)C`, the resulting change in its entropy, taking latent heat of ice to be `80 cal//g` isA. `8xx10^(4)cal//K`B. `80cal//K`C. `293 cal//K`D. `273 cal//K`

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