When `1` mole of a monatomic gas is mixed with `3` moles of a diatomic gas, the value of adiabatic exponent `gamma` for the mixture isA. `5/3`B. `1.5`C. `1.4`D. `13/9`

When `1` mole of a monatomic gas is mixed with `3` moles of a diatomic

1.	When `1` mole of a monatomic gas is mixed with `3` moles of a diatomic gas, the value of adiabatic exponent `gamma` for the mixture isA. `5/3`B. `1.5`C. `1.4`D. `13/9`
Answer» Correct Answer - D `(n_1+n_2)/(gamma-1) = (n_1)/(gamma_(1)-1) + (n_2)/(gamma_(2)-1)` `(1+3)/(gamma-1) = (1)/(5/3-1) + 3/(7/5 -1)` `4/(gamma-1) = 3/2+15/2 = 9` or `gamma -1 =4/9 implies gamma = 1 + 4/9 = 13/9`.

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When `1` mole of a monatomic gas is mixed with `3` moles of a diatomic gas, the value of adiabatic exponent `gamma` for the mixture isA. `5/3`B. `1.5`C. `1.4`D. `13/9`

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