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When 10 A current passes through 12Omega resistance, maximum voltage across it is …….. |
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Answer» 20 V SIMILARLY in case of voltage `V_(dc)=V_(ac)=V_(rms)=V_m/sqrt2`(where `V_(rms)`= rms value of voltage and `V_m` = maximum voltage ) `I_m=sqrt2I_(rms)` =1.414 x 10 =14.14 A `therefore` MAX. voltage `V_m=I_m R` =14.14 x 12 = 169.68 V |
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