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When 10 A current passes through 12Omega resistance, maximum voltage across it is ……..

Answer»

20 V
90 V
169.68 V
120 V

Solution :In CASE of CURRENT `I_(dc)=I_(ac)=I_(rms)=I_m/sqrt2` (where `I_(rms)`=rms value of current and `I_m` = maximum current )
SIMILARLY in case of voltage `V_(dc)=V_(ac)=V_(rms)=V_m/sqrt2`(where `V_(rms)`= rms value of voltage and `V_m` = maximum voltage )
`I_m=sqrt2I_(rms)`
=1.414 x 10
=14.14 A
`therefore` MAX. voltage `V_m=I_m R`
=14.14 x 12
= 169.68 V


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