1.

When 10 resistors, each with resistance (1)/(10) Omega are connected in parallel , equivalent resistance will be ......

Answer»

<P>`1 OMEGA`
`100 Omega `
`(1)/(100) Omega`
`10 Omega`

SOLUTION :`(1)/(100) Omega`
`(1)/(R_(p))= (1)/((1)/(10))+ (1)/((1)/(10)) + (1)/((1)/(10))+ .... + 10 ` times
` = (10)/((1)/(10)) `
`(1)/(R_(p)) = (100)/(1) "" THEREFORE R_(p) = (1)/(100) Omega`


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