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When 12.0 g of carbon reacted with limited quantity of oxygen, 57.5 kcal of heat was produced, calculate the number of moles of CO produced `(Delta_(f)H(CO_(2))=-94.5 cal, Delta_(f)H(CO)= -21.41kcal.`A. 0.5 molB. 0.46 molC. 0.64 molD. 0.74 mol |
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Answer» Correct Answer - A `12g C=1` mole, suppose CO produced `=x` moles. Then `CO_(2)` produced `=(1-x)` mole `:. X(-21.41)+(1-x)(-94.05)= -57.5` This on solving gives `x=0.54` mole. |
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