When `12.0g` of `C` reacted with a limited quantity of oxygen, `57.5 kcal `of heat was produced. Calculate the number of `CO` and number of moles of `CO_(2)` produced. Given `C +O_(2) rarr CO_(2), Delta_(f)H = - 94.05 kcal` `C +1//2O_(2) rarr CO, Delta_(f)H =- 26.41 kcal `

When `12.0g` of `C` reacted with a limited quantity of oxygen, `57.5 k

1.	When `12.0g` of `C` reacted with a limited quantity of oxygen, `57.5 kcal `of heat was produced. Calculate the number of `CO` and number of moles of `CO_(2)` produced. Given `C +O_(2) rarr CO_(2), Delta_(f)H = - 94.05 kcal` `C +1//2O_(2) rarr CO, Delta_(f)H =- 26.41 kcal `
Answer» `C = (12)/(12) = 1 mol` `{:(C+,O_(2)rarr,CO_(2),DeltaH_(1)=-94.05kcal),(x,x,),(C+,(1)/(2)O_(2)rarr,CO,DeltaH_(2) =- 26.41 kcal),((1-x),,(1-x)):}` `:.x (-94.05) +(1-x)(-26.41) =- 57.5` `x = 0.46 mol of CO_(2)` `1 -x = 0.54 mol of CO`

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When `12.0g` of `C` reacted with a limited quantity of oxygen, `57.5 kcal `of heat was produced. Calculate the number of `CO` and number of moles of `CO_(2)` produced. Given `C +O_(2) rarr CO_(2), Delta_(f)H = - 94.05 kcal` `C +1//2O_(2) rarr CO, Delta_(f)H =- 26.41 kcal `

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