1.

When 2.5Omega shunt is connected with 25Omega resistance of galvanometer, what fraction of total current I would pass through galvanometer?

Answer»

`I_(G)/I=1/11`
`I_(G)/I=1/10`
`I_(G)/I=1/9`
`I_(G)/I=2/11`

SOLUTION :`I_(G)=IxxS/(S+G)`
= `Ixx2.5/(2.5+25)`
`thereforeI_(G)/I=2.5/27.5=1/11`


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