Saved Bookmarks
| 1. |
When 2.5Omega shunt is connected with 25Omega resistance of galvanometer, what fraction of total current I would pass through galvanometer? |
|
Answer» `I_(G)/I=1/11` = `Ixx2.5/(2.5+25)` `thereforeI_(G)/I=2.5/27.5=1/11` |
|