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InterviewSolution
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When 22.4 litres of H2 (g) is mixed with 11.2 litresof Cl (g). each at S.T.P, the moles of HCI(g)formed is equal to(1) 1 mol of HCI (g)(2) 2 mol of HCI (9)(3) 0.5 mol of HCI (g)(4) 1.5 mol of HCI (g)AIPMT-2014 |
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Answer» H2 + CL2-> 2HCL22.4 L 22.4 L 2×22.4 22.4 Litres hydrogen reacts with 22.4 litre of chlorine to give 44.8 L of HCLthe given volume of chlorine is 11.2 Lhere chlorine is the liming reagents as its . first consumed22.4 Litre of chlorine gives 73 litre of HCLso , 11.2 l gives 44.8/22.4 × 11.2 = 22.4 of HCL is formedthat means no. of mole = 1because 1 mole of any gases occupies 22.4 L at STP the answer is A . 1 mole of HCL (g) |
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