1.

When 30.0 gof a non - volatilesolute havingthe empirical fromual CH_(2)Oare dissolvedin 800g of water, thesolutionfreezes at- 1.16^(@)C . Whatis the molecularformula of the solute ? (k_(f)for water = 1.86 K m^(-1))

Answer»


Solution :`M_(B)= (k_(F) xx w_(B) xx 1000)/(w_(A) xx Delta T_(f))= (1.86 xx 30.0 xx 1000)/(800 xx 1.16)`
`M_(B) = 60.1`
` n = ("Mol.formula MASS")/("Empirical FORMUAL mass") = (60)/(30) = 2`
MOLECULAR formual ` = (CH_(2)O)_(2) = C_(2)H_(4)O_(2)` .


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