1.

When 32.25 g of ethyl chloride is subjected to dehydrohalogenation reaction, the yield of alkene formed is 50%. The mass of the product formed is (atomic mass of Cl = 35.5)

Answer»

14 gm
28 gm
`64.5` gm
7 gm

Solution :`CH_(2)H_(5)Cloverset(-HCl)rarrC_(2)H_(4)`
`{:(64.5""28),(32.25""14):}`
`64.5gm C_(2)H_(5)Cl` GIVES `28 gm` of `C_(2)H_(4)`
`32.25 gm C_(2)H_(5)Cl` gives `= (28 xx 32.25)/(64.5) = 14`
`= 14 gm`of `C_(2)H_(4)`
Obtained producted is `50%` so mass of obtained alkene
`=(14)/(2) = 7 gm`.


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