When 35 mL of 0.15 M lead nitrate solution is mixed with 20 mL of 0.1 – InterviewSolution

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1.	When 35 mL of 0.15 M lead nitrate solution is mixed with 20 mL of 0.12 M chromic sulphate solution, ×10−5 moles of lead sulphate precipitate out. (Round off to the nearest integer).
Answer» When $35 m L$ of $0.15 M$ lead nitrate solution is mixed with $20 mL$ of $0.12 M$ chromic sulphate solution, $\times 10^{- 5}$ moles of lead sulphate precipitate out. (Round off to the nearest integer).

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