1.

When 50Omega resistance is connected to one voltmeter, its range is obtained upto V volt. Now, instead of 50Omega, when 500Omega resistance is connected to this voltmeter, its range is obtained upto 2 V volt. Find resistance of this voltmeter.

Answer»

`100Omega`
`200Omega`
`300Omega`
`400Omega`

SOLUTION :We have `R=G(n-1)""...(1)`
(i) `R_(1)=G(n_(1)-1)`
`therefore50=G(n_(1)-1)=Gn_(1)-G""...(2)`
(ii) `R_(2)=G(n_(2)-1)`
`therefore500=G(2n_(1)-1)=2Gn_(1)-G""...(3)`
Multiplying equation (2) by 2, we get,
`100=2Gn_(1)-2G""...(4)`
Subtracting equation (4) from equation (3) we get,
400 = G
`thereforeG=400Omega`


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