When 5a2b+10b2c2−21ab+32 is subtracted from 50−20b2c2−4bc−ac� – InterviewSolution

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1.	When 5a2b+10b2c2−21ab+32 is subtracted from 50−20b2c2−4bc−ac−5ab, we get
Answer» When $5 a^{2} b + 10 b^{2} c^{2} - 21 a b + 32$ is subtracted from $50 - 20 b^{2} c^{2} - 4 b c - a c - 5 a b$ , we get

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