1.

When 6 gm urea dissolve in 18 gm H_(2)O. The mole fraction of urea is

Answer»

`(10)/(10.1)`
`(10.1)/(10)`
`(10.1)/(0.1)`
`(0.1)/(10.1)`

Solution :Mole FRACTION `X=(N)/(n + N)=((6)/(60))/((6)/(60)+(180)/(18))=(0.1)/(10.1)`.


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