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When a^2+b^2+3c^2=250 and ab+bc+ca=3 find the value of a+b+c |
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Answer» Answer: It is GIVEN that, a²+b²+c²=250 ab+bc+ac=3 squaring on the both SIDES, (a+b+c)²=a²+b²+c²+2(ab+bc+ac) (a+b+c)²=250+6=256 a+b+c=16 Step-by-step explanation: Hope it HELPS you frnd....... |
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