When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L+l). The elastic potential energy stored in the extended wire isA. `(1)/(2)MgL`B. `Mgl`C. `MgL`D. `(1)/(2)Mgl`

When a block of mass M is suspended by a long wire of length L, the le

1.	When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L+l). The elastic potential energy stored in the extended wire isA. `(1)/(2)MgL`B. `Mgl`C. `MgL`D. `(1)/(2)Mgl`
Answer» Correct Answer - D Strain `=(l)/(L)`, stress `=(Mg)/(A)` Energy `=(1)/(2)xx"stress"xx"strain"xx"volume"` `=(1)/(2)xx(Mg)/(A)xx(l)/(L)xxAxxL` `=(1)/(2)Mgl`

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When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L+l). The elastic potential energy stored in the extended wire isA. `(1)/(2)MgL`B. `Mgl`C. `MgL`D. `(1)/(2)Mgl`

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