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When a capacitor of small capacitance is connected in series withL-R circuit. The alternating current in the circuit increases. Explain why ? |
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Answer» Solution :Addition of capacitor in the GIVEN CIRCUIT decreases the impedance Z of the circuit and hence INCREASES current I in the circuit as `I = (V)/(Z)` where `Z = sqrt(R^(2) + X_(L)^(2))` WITHOUT capacitor and new `Z = sqrt(R^(2) + (X_(L) - X_(C))^(2))` with capacitor. |
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