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When a coil is connected to a 100 V D.C. supply, the current is 2 A. When the same coil is connected to A.C. source `E=100sqrt(2) sin omega t`, the current is 1 A. Find the inductive reactance used in the circuit. |
Answer» In D.C. circuit `I =(V)/(R) rArr "So, " R=(V)/(I) = 50 Omega` In A.C. `I_("rms")=(V_("rms"))/(Z)rArr 1 = (100)/(z) rArr Z=100 Omega` Now `Z=sqrt(R^(2)+X_(L)^(2))rArr X_(L)=50sqrt(3)Omega` |
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