When a coordination compound CrCl_(3), 4H_(2)O is mixed with silver nitrate solution, one mole of silver chloride is precipitated per mole of the compound. There are no free solvent molecules in that compound. Assign the secondary valence to the metal and write the structural formula of the compound.

When a coordination compound CrCl_(3), 4H_(2)O is mixed with silver ni

1.	When a coordination compound CrCl_(3), 4H_(2)O is mixed with silver nitrate solution, one mole of silver chloride is precipitated per mole of the compound. There are no free solvent molecules in that compound. Assign the secondary valence to the metal and write the structural formula of the compound.
Answer» Solution :`(i)` When a coordination compound `CrCl_(3).4H_(2)O` is mixed with silver nitrate solution, one mole of silver chloride is precipitated per mole of the compound. This shows `CrCl_(3).4H_(2)O` complex compound contains one `CI^(oplus)` counter ion. `(ii)` Therefore are no free solvent molecules in `CrCl_(2).4H_(2)O` compound, this shows water molecules are coordinated with central metal ion. `(iii)` Therefore, coordination complex is `[CrCl_(2).4H_(2)O]Cl` Secondary value of the central metal ion is `2Cl^(oplus)` and `4H_(2)O`. Hence coordination number is`6`. `(IV)` Wener.s structure of `[CrCl_(2).(H_(2)O)_(4)]Cl`