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When a current drawn from a battery is 0.5A, its terminal potential difference is 20V. And when current drawn from it is 2.0A, the terminal voltage reduces to 16V. Find out, e.m.f and internal resistance of the battery. |
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Answer» Solution :We known `V=E-Ir`, `I=0.5A, V=20` Volt, we have `20=E-0.5r"…..(i)"` `I=2A, V=16" Volt, we have "16=E-0.2r"…..(ii)"` From EQS (i) and (ii) `2E-r=40` and `E-2r=16` SOLVING we GET `E=21.3V, r=2.675Omega`. |
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