When a die is thrown, find the probability of getting no.greater than

1.	When a die is thrown, find the probability of getting no.greater than 4
Answer» Answer: Hence, the required probability of getting a number greater than 4, P(E) = 1/3. Step-by-step explanation: GIVEN : A die is thrown once . A die has 6 faces marked as 1, 2, 3, 4, 5 and 6. If we throw one die then there possible outcomes are as follows: 1, 2, 3, 4, 5 and 6 Number of possible outcomes are = 6 Let E = Event of getting a number greater than 4 Number greater than 4 on a die are : 5,6 Number of outcome FAVOURABLE to E = 2 Probability (E) = Number of favourable outcomes / Total number of outcomes P(E) = 2/6 = 1/3 Hence, the required probability of getting a number greater than 4, P(E) = 1/3 HOPE THIS ANSWER HELPS YOU…... pls mark me as the BRAINLIEST

When a die is thrown, find the probability of getting no.greater than 4

Answer»

Answer:

Hence, the required probability of getting a number greater than 4, P(E) = 1/3.

Step-by-step explanation:

GIVEN : A die is thrown once .

A die has 6 faces marked as 1, 2, 3, 4, 5 and 6.

If we throw one die then there possible outcomes are as follows: 1, 2, 3, 4, 5 and 6

Number of possible outcomes are = 6

Let E = Event of getting a number greater than 4

Number greater than 4 on a die are : 5,6

Number of outcome FAVOURABLE to E = 2

Probability (E) = Number of favourable outcomes / Total number of outcomes

P(E) = 2/6 = 1/3

Hence, the required probability of getting a number greater than 4, P(E) = 1/3

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