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When a glass prism of refracting angle `60^(@)` is immersed in a liquid its angle of minimum deviation is `30^(@)`. The critical angle of glass with respect to the liquid medium isA. `42^(@)`B. `45^(@)`C. `50^(@)`D. `52^(@)` |
Answer» Correct Answer - B `A=60^(@), delta_(m)=30` so`mu=(sin((A+delta_(m))/(2)))/(sin((A)/(2)))` `mu=(sin((600^(@)+30^(@))/(2)))/(sin((60^(@))/(2)))=(sin 45^(@))/(sin 30^(@))=sqrt(2)` Also `mu=(1)/(sinC)impliesC=sin^(-1)((1)/(mu))impliesC=45^(@)` |
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