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When a helium nucleus revolves in a circular orbit of radius 0.8 m,if it takes 2 sec to comlete one revolution.find magnetic field produced at the centre would be _____ T. |
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Answer» `10^(-18)mu_(0)` `thereforeB=(mu_(0)I)/(2a)=(mu_(0)Qf)/(2a)""(becauseI=Qf)` `thereforeB=(mu_(0)xx2xx1.6xx10^(-19)XX1)/(2xx0.8)` `thereforeB=2xxmu_(0)xx10^(-19)T` |
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