1.

When a 'J' shaped conducting rod rotating in its own plane with constant angular velocity omega, avout one of its end P, in a uniform magnetic field vec(B) directed normally into the plane of paper) then magnetic of emf induced across it will be

Answer»

`Bomegasqrt(L^(2)+l^(2))`
`1/2 BomegaL^(2)`
`1/Bomega(L^(2)+l^(2))`
`1/2Bomegal^(2)`

SOLUTION :`e=1/2Bomega(SQRT(l^(2)+L^(2)))^(2)`
`e=1/2Bomega(l^(2)+L^(2))`


Discussion

No Comment Found

Related InterviewSolutions