InterviewSolution
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InterviewSolution
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When a metal rod M is dipped into an aqueous colourless concetrated solution of compound N, the solution turns light blue. Addition of aqueous NaCl to the blue solution gives a white precipitate O. Addition of aqueous `NH_3` dissolves O and gives an intense blue solution. Q. The final solution contains.A. `[Pb(NH_(3))_(4)]^(2+)` and `[CoCl_(4)]^(2-)`B. `[Al(NH_(3))_(4)]^(3+)` and `[Cu(NH_(3))_(4)]^(2+)`C. `[Ag(NH_(3))_(2)]^(+)` and `[Cu(NH_(3))_(4)]^(2+)`D. `[Ag(NH_(3))_(2)]^(+)` and `[Ni(NH_(3))_(6)]^(2+)` |
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Answer» Correct Answer - C `Cu(M) +AgNO_(3) ( "aqueous colorless solution ") rarr "Resultant solution " underset((N)(blue solution)")((Cu(NO_(3))_(2)+AgNO_(3)))` Note `:` Here it is considered that complete `AgNO_(3)` is not utilized in the reaction `AgNO_(3)+NaClrarrunderset((O)(whiter ppt.)")(AgCldarr+NaNO_(3))` Solution containing white ppt. of AgCl also contains `Cu(NO_(3))_(2)` which developed deep blue colouration with aqueous `NH_(3)` solution . `AgCldarr ("white")+2NH_(3)(aq). rarr [Ag(NH_(3))_(2)]^(+)` `Cu(NO_(3))_(2)(aq.)+4NH_(3)(aq.) rarr underset("(deep blue coloration)")([Cu(NH_(3))_(4)](NO_(3))_(2)` So, Metal rod M is Cu. The compound N is `AgNO_(3)` and the final solution contains `[Ag(NH_(3))_(2)]^(+)` and `[Cu(NH_(3))_(4)]^(2+)` |
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