When a mixture of 10 moles of `SO_(2)` and 16 moles of `O_(2)` were passed over a catalyst, 8 moles of `SO_(3)` were formed at equilibrium. The number of `SO_(2) and O_(2)` remaining unreacted were:A. 2,12B. 12,2C. 3,10D. 3,10

When a mixture of 10 moles of `SO_(2)` and 16 moles of `O_(2)` were pa

1.	When a mixture of 10 moles of `SO_(2)` and 16 moles of `O_(2)` were passed over a catalyst, 8 moles of `SO_(3)` were formed at equilibrium. The number of `SO_(2) and O_(2)` remaining unreacted were:A. 2,12B. 12,2C. 3,10D. 3,10
Answer» Correct Answer - A `2SO_(2)(g)+O_(2)(g) Leftrightarrow 2SO_(3)(g)` `{:(,t=0,10,16,0),(,t_(eq),(10-2x),(16-x),0),(, ,(2x=8), ,x=4):}` `therefore "Remaining "SO_(2)=10-8=2"mol"` ` "Remaining "O_(2)=16-4=12"mol"`

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When a mixture of 10 moles of `SO_(2)` and 16 moles of `O_(2)` were passed over a catalyst, 8 moles of `SO_(3)` were formed at equilibrium. The number of `SO_(2) and O_(2)` remaining unreacted were:A. 2,12B. 12,2C. 3,10D. 3,10

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