1.

When a mixture of NaBr and NaCl is separately digested with `H_2SO_4` all the halogens are expelled and `Na_2SO_4` is formed quantitatively with a particular mixture, it was found that the weight of `Na_2SO_4` obtained was precisely the same as the weight of `NaBr+NaCl` mixture taken. Calculate the ratio of the weight of NaCl and NaBr in the mixture.

Answer» Let the weight of `NaCl` be x g and the weight of NaBr be y g. ,brgt We have to calculate `(x)/(y)`
`2NaCl-=Na_2SO_4`
`2xx58.5g of NaCl-=142g of Na_2SO_4`
`x g of NaCl-=(142)/(2xx58.4)xx x g of Na_2SO_4`
`2NaBr-=Na_2SO_4`
`2xx103g of NaBr-=142 g of Na_2SO_4`
`y g of NaBr-=(142)/(2xx103)xx x g of Na_2SO_4`
`therefore(142x)/(2xx58.5)+(142x)/(2xx103)=x+y`
`1.21x-x=y-0.69y`
`0.21x=0.31y`
`(x)/(y)=(0.31)/(0.21)=1.475`
The ratio of weights of `NaCl:NaBr` is `1.476:1`


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