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When a negative charge is moved from surface of Earth to a certain height, its gravitational potential energy ...... . |
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Answer» remains constant `U_(1) = -(GMm)/(R)` ( Where m = mass of given negative charge ) At HEIGHT h above surface of Earth `U_(2)=-(GMm)/(R+h)` `:. U_(2)-U_(1)=-(GMm)/(R+h)-((-GMm)/(R))` `:. U_(2)-U_(1)=GMm((1)/(R)-(1)/(R+h))` Here `R lt R +himplies (1)/(R) gt (1)/(R+h)` `:. U_(2)-U_(1)gt 0` `:. U_(2) gt U_(1)` Gravitational potential energy increases as we move away from surface of Earth. |
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