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When a neutron induces fisssion in a ._(92)U^(235) nucleus, about 185MeV of usable enegry is released. If a reactor continuously generates 100MW of power using ._(92)U^(235)as fuel, then how long will it take for 1 kg of the uranium to be used up? |
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Answer» Solution :Number of fissions `= (m)/(M)N_(A)` Energy released, `E = (m)/(M) N_(A) xx 185 xx 1.6 xx 10^(-13) J` POWER `= (E)/(t) = (mN_(A)xx185xx1.6xx10^(-13))/(235xxt) = 100 xx10^(6)` `t = (10^(3)xx6.023 xx 10^(23)xx185xx1.6xx10^(-13))/(235xx10^(8)) sec` `=7.57 xx 10^(5)s = (7.57 xx 10^(5))/(24xx3600)` `= 8.76 DAYS` |
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