InterviewSolution
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InterviewSolution
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When a nucleus with atomic number `Z` and mass number `A` undergoes a radioactive decay process, (i) Both `Z` and `A` will decrease, if the process is `alpha` decay (ii) `Z` will decrease but `A` will not change, if the process is `beta^(+)-`decay (iii) `Z` will increase but `A` will not change, if the process is `beta-`decay (iv) `Z` and `a` will remain uncharged, if the prices is `gamma` decayA. both Z and A will decrease, If the process is `alpha` decayB. Z will decrease but A will not change, if the process is `beta^(+)` decayC. Z will decrease but A will not change, if the process is `beta^(-)` decayD. Z and A will remain unchanged, if the process is `beta` decay |
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Answer» Correct Answer - A::B::D `alpha` decays : `._(2)He^(4)`, so both Z & A decreases. `beta^(+)` decays : `._(+1)e^(0)`, so A will not change but Z will change (decreases) `beta^(-)` decat : `._(-1)e^(0)`, so A will not change but Z will change (increases) `gamma` decays : no change in A & Z. |
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