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Answer» no current flows
the DEPLETION region is increased
the depletion reagion is reduced
the HEIGHT of the POTENTIAL barrier is reduced Solution :In reverse biasing, the applied voltage`V` on the `N-` side is positive and is negative on the `p-`side. The applied bias `V` and the barrier potential `V_(B)` are in the same direction MAKING the effective junction potential `V+V_(B)`. As a result, the junction width will increase. The higher junction potential would restrict the flow of majority carriers to a much greater extent. However, such a field will favour the flow of minority carriers. So, reverse bias current will be due to the minority carriers only.
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