InterviewSolution
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InterviewSolution
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When a particle is projected at an angle to the horizontal, it has range R and time of flight `t_(1)`. If the same projectile is projected with same speed at another angle to have the saem range, time of flight is `t_(2)`. Show that: `t_(1)t_(2)=(2R//g)` |
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Answer» `t_(1)=(2u sin theta)/(g)` and `t_(2)=(2u sin (90^(@)-theta))/(g)=(2u cos theta)/(g)` `therefore t_(1)t_(2)=(2u sin theta)/(g)xx(2u cos theta)/(g)=(2)/(g)((u^(2)sin 2theta)/(g))=(2R)/(g)` |
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