1.

When a plot of log k versus 1//T of chemical reaction is made, the energy of activation is given by the slope of straight line

Answer»

obtained
MULTIPLIED by + 2.303 R
multipiled by -2.303 R
divided by +2.303 R

Solution :Logarithmic form of Arrhenius equation is :
log `k = log A - (E_(a))/(2.303 RT) xx (1)/(T)`
It is a straight LINE equation (y= c + mx)

slope `=(-E_a)/(2.303R)or E_a="slope"xx(-2.303R)`


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