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When a projectile is moving at 60 m s^(-1) at the highest point of its trajectory, it explodes into two equal parts. One part moves vertically up with a velocity of 50 ms^(-1) . The magnitude of velocity of other part is: |
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Answer» `50ms^(-1)` Applying momentum conservation along X-axis, we get `mv_(x)=(2m)60` or `v_(x)=120ms^(-1)` Applying momentum conservation along Y-axis, we get `mv_(y)=m(50)` or `v_(y)=50ms^(-1)` Velocity of the other part, v `sqrt(120^(2)+50^(2))MS^(-1)` |
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