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When a resistance of 10Omega is connected in series with the unknown resistance R the balancing length is found to be 50cm . When 10 Omega is removed the balancing length is shifted to 40 cm. What will be the value of unknown resistance R? |
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Answer» SOLUTION :LET `R^1` be the resistance in the box Then (R+10)=`R^1xx50/50=R^1`………(1) R=`R^1xx40/60=0.667R^1`……2 from (1) and (2) R=0.667(R+10) R=20`Omega` |
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