1.

When a rubber-band is stretched by a distance x, it exerts a restoring force of magnitude F = ax + bx2 where a and b are constants. The work done in stretching the unstretched rubber band by L is :

Answer»

`1/2 ((AL^(2))/(2)+(bL^3)/(3))`
`aL^(2)+bL^(3)`
`(1)/(2)(aL^(2)+bL^(2))`
`(aL^(2))/(2) +(bL^3)/(3)`

Solution :Here,`work done = FORCE xx distance`
Now `F=ax+bx^2`
`:.dW=Fdx=int_o^L(ax+bx^2)DX=(aL^2)/(2)+(bL^3)/(3)`.


Discussion

No Comment Found

Related InterviewSolutions