1.

When a sphere of moment of inertia I moves down an inclined plane, the percentage of energy which is rotational, is approximately :

Answer»

`100%`
`72%`
`28%`
NONE of these

Solution :T.E. = Linear K.E. + Rot. K.E.
`=(1)/(2)mv^(2)+(1)/(2)Iomega^(2)`
`=(1)/(2)mv^(2)+(1)/(2).(2)/(5)mr^(2)omega^(2)=(1)/(2)mv^(2)+(1)/(5)mv^(2)`
`=(7)/(10)mv^(2)=(7)/(10)xx50xx25=875ergs`


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