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When a string is divided into three segments of lengths `l_(1),l_(2) and l_(3)` the fundamental frequencies of these three segments are `v_(1), v_(2) and v_(3)` respectively. The original fundamental frequency (v) of the string isA. `sqrt(v)= sqrt(v_(1))+sqrt(v_(2))+sqrt(v_(3))`B. `v= v_(1) + v_(2)+v_(3)`C. `1/v=1/v_(1) + 1/v_(2)+1/v_(3)`D. `1/sqrt(v)= 1/sqrt(v_(1))+1/sqrt(v_(2))+1/sqrt(v_(3))` |
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Answer» Correct Answer - c The fundamental frequency of string `v=1/(2l)sqrt(T/m)` `therefore v_(1)l_(1)=v_(2)l_(2)=v_(3)l_(3)=k ... (i) ` Form Eq. (i), `l_(1)=k/v_(1), l_(2)=k/v_(2), l_(3)=k/v_(3)` Original length, `l=k/v` Here, `l=l_(1)+L_(2)+l_(3)` `k/v=k/v_(1)+k/v_(2)+k/v_(3)` `rArr 1/v=1/v_(1)+1/v_(2)+1/v_(3)` |
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