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In a sonometer wire, the tension is maintained by suspending a 50.7 kg mass from the free end of the wire. The suspended mass has a volume of 0.0075 m 3. The fundamental frequency of the wire is 260 Hz . If the suspended mass is completely submerged in water, the fundamental frequency will become (take `g = 10 ms^(-2)`) [A. 220 HzB. 230 HzC. 240 HzD. 260 Hz |
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Answer» Correct Answer - C `n_2/n_1 = sqrt(T_2/T_1)` By archimedes principle `=T_1-T_2` `=vrhog` = loss of weight in water `therefore T_2=T_1-vrhog` `n_2/n_1 = sqrt((T_1-vrhog)/(T_1))` `=sqrt(((50.7-7.5xx10^(-3)xx10^3)g)/(50.7g))` `=sqrt((43.2)/(50.7)) = sqrt(144/169)` `n_2/n_1 = 12/13 therefore n_2 = 12/13 xx260 = 240Hz` |
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