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When a system is taken from state i to state f along the path iaf, it is found that `Q=50 cal and W=20 cal`. Along the path ibf `Q=36cal`. W along the path ibf is A. `14 cal.`B. `6 cal.`C. `16 cal.`D. `66 cal.` |
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Answer» Correct Answer - B Along the path `iaf`, Increase in internal energy, `U_(1)=Q_(1)-W_(1)= 50-20= 30Cal.` Along the path `ibf` Increase in inernal energy, `U_(2)=Q_(2)-W_(2)` `U_(2)= 36-W` As `U_(2)=U_(1) :. 36-W= 30` `W= 36-30= 6 Cal` |
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